Two electric dipoles of moment P and 64 P are placed in opposite direction on a line at a distance of 25 cm. The electric field will be zero at point between the dipoles whose distance from the dipole of moment P is
Text Solution
Verified by ExpertsA
Suppose neutral point N lies at a distance x from dipole of moment p or at a distance x 2 from dipole of 64 p.
At N |E. F. due to dipole ① ① |= |E. F. due to dipole ② ‚ |
⇒ ⇒ $\frac{1}{4 \pi \varepsilon_0} \cdot \frac{2p}{x^3} = \frac{1}{4 \pi \varepsilon_0} \cdot \frac{2(64 p)}{(25 - x)^3}$
⇒ ⇒ $\frac{1}{x^{3}} = \frac{64}{(25 - x)^{3}}$ ⇒ ⇒ x = 5 cm.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems